1,200t^2=10=

Solution for 1,200t^2=10= equation:

1.200t^2=10=

We move all terms to the left:

1.200t^2-(10)=0

a = 1.200; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·1.200·(-10)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*1.200}=\frac{0-4\sqrt{3}}{2.4}
=-\frac{4\sqrt{3}}{2.4}
=-\frac{2\sqrt{3}}{1.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*1.200}=\frac{0+4\sqrt{3}}{2.4}
=\frac{4\sqrt{3}}{2.4}
=\frac{2\sqrt{3}}{1.2}
$